This is something I haven't really thought of before, typically when I implement a file upload for an image the preview happens after. However, there is actually a really simple way to get a preview of it before the actual upload happens to the server. Let's take a look at an example.
To start with, you need a basic form with a file input and an element that will preview the image: The following solution leverages the oninput function to set the src of the img tag with the id of pic. This can also be accomplished with a JavaScript array event for the onchange type: Both methods work basically the same way as they rely on the URL.createObjectURL function. Published on Jun 19, 2022 Tags: JavaScript
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Jamie Munro is the author of ASP.NET MVC 5 with Bootstrap and Knockout.js,
Knockout.js: Building Dynamic Client-Side Web Applications,
20 Recipes for Programming MVC 3,
and 20 Recipes for Programming PhoneGap. He has been developing websites and web applications for over 20 years. Jamie began his writing career in 2009. As the success of Jamie's blog grew, he turned his writing passion to books about web development in hopes that his many years of experience could be passed on to his readers. No matter the programming language you're looking to learn, I've hopefully compiled an incredible set of tutorials for you to learn; whether you are beginner
or an expert, there is something for everyone to learn. Each topic I go in-depth and provide many examples throughout. I can't wait for you to dig in
and improve your skillset with any of the tutorials below.
<form method="POST" action="myServerSideCode.php">
<label for="image">Upload image:</label>
<input id="image" type="file" oninput="pic.src=window.URL.createObjectURL(this.files[0])">
<img id="pic" />
</form>
image.onchange = evt => {
const [file] = image.files
if (file) {
pic.src = URL.createObjectURL(file)
}
}
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